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x^2-69x+69=0
a = 1; b = -69; c = +69;
Δ = b2-4ac
Δ = -692-4·1·69
Δ = 4485
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-69)-\sqrt{4485}}{2*1}=\frac{69-\sqrt{4485}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-69)+\sqrt{4485}}{2*1}=\frac{69+\sqrt{4485}}{2} $
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